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8x^2-104x+336=0
a = 8; b = -104; c = +336;
Δ = b2-4ac
Δ = -1042-4·8·336
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-8}{2*8}=\frac{96}{16} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+8}{2*8}=\frac{112}{16} =7 $
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